1 Million+
Questions
50k +
Active Users
24hrs max.
Answering Time
Question : Raghav went to a shopping mall to purchase clothes. He had two coupons with him, but only one can be used on a single day. Using the first coupon, a total discount of 30% could be obtained on the total amount. Using the second coupon, he will get 80% off on the price of the costliest shirt if he buys at least 3 shirts. What is the price at which Raghav can purchase 3 shirts at a minimum price if the prices of the three shirts are Rs.1,250, Rs.1,540, and Rs.1,375?
Option 1: INR 2,760
Option 2: INR 2,915.50
Option 3: INR 2,775
Option 4: INR 2,933
Correct Answer: INR 2,915.50
Solution : For 30% discount: Actual cost price = (1250 + 1540 + 1375) $\times$ 70% = 4165 $\times$ 70% = 2915.5 For 80% off on the price of the costliest shirt: Actual cost price = 1250 + 1540 $\times$ 20% + 1375 = 1250 +
Question : Directions: In the following question, a sentence is given with a blank that is to be filled in with an appropriate word. Four alternatives are suggested; choose the correct alternative out of them as your answer.
He waited with ______ breath for the door to open.
Option 1: baited
Option 2: bated
Option 3: beaten
Option 4: bitten
Correct Answer: bated
Solution : The correct choice is the second option.
Explanation:
Bated means to hold back or suspend, and the phrase "bated breath" is a common expression used to describe someone who is holding his breath or waiting with great anticipation.
The meanings of the other options are
Question : Which of the following neighbours of India has the highest population density?
Option 1: Bangladesh
Option 2: Sri Lanka
Option 3: China
Option 4: Pakistan
Correct Answer: Bangladesh
Solution : The correct option is Bangladesh.
Bangladesh is the most densely populated, with 1,330 people per km². It is almost three times as dense as its neighbour, India. It’s followed by Rwanda (571), South Korea (531), Lebanon (523), and the Netherlands (523).
Question : Directions: Three statements are given, followed by three conclusions numbered I, II, and III. Assuming the statements to be true, even if they seem to be at variance with commonly known facts, decide which of the conclusions logically follow(s) from the statements. Statements: Some plants are flowers. Some flowers are fruits. All flowers are gardens. Conclusions: I. Some gardens are plants. II. Some fruits are gardens. III. Some gardens are flowers.
Option 1: All of the conclusions follow
Option 2: Only conclusions I and III follow
Option 3: Only conclusions I and II follow
Option 4: Only conclusions II and III follow
Correct Answer: All of the conclusions follow
Solution : The possible Venn diagram according to the given statements is as follows –
Let's analyse the conclusions – Conclusion I: Some gardens are plants – From the Venn diagram, the circle of the garden intersects the circle of the garden and
Question : The fraction equivalent to $\frac{1}{5} \%$ is:
Option 1: $\frac{1}{125}$
Option 2: $\frac{1}{200}$
Option 3: $\frac{1}{40}$
Option 4: $\frac{1}{500}$
Correct Answer: $\frac{1}{500}$
Solution : Lets find out the $\frac{1}{5} \%$. So, $\frac{1}{5} \%$ = $\frac{\frac{1}{5}}{100} = \frac{1}{500}$ Hence, the correct answer is $ \frac{1}{500}$.
Question : Directions: Select the combination of letters that when sequentially placed in the blanks of the given series will complete the series. G_ IJG_HIJGGH_ IJGGHH _IJ
Option 1: HIJG
Option 2: HGHI
Option 3: JGGJ
Option 4: GHHI
Correct Answer: HGHI
Solution : Given: G_ IJG_HIJGGH_ IJGGHH _IJ
To fill the series we have to divide the series – G_ IJ/G_HIJ/GGH _ IJ/GGHH _IJ Let's check each option – First option: HIJG; GHIJ/GIHIJ/GGHJIJ/GGHHGIJ (No repeated pattern has been found.) Second
Question : The given graph shows the number (in hundreds) of trees axed in four cities during the period 2016-2020. Find the year in which the least number of trees are axed.
Option 1: 2016
Option 2: 2020
Option 3: 2019
Option 4: 2017
Correct Answer: 2019
Solution : In 2016, the number of trees axed = 18 + 20 + 18 + 25 = 81 In 2020, the number of trees axed = 22.5 + 21 + 20 + 17.5 = 81 In 2019, the number of trees axed = 24.4 + 19.5
Question : Directions: In the following question, some parts of the sentence have errors, and some are correct. Find out which part of the sentence has an error. The number of that part is the answer. If a sentence is error-free, your answer is "No Error".
We received much help from the neighbours.
(1) We received
(2) much help
(3) No Error
(4) from the neighbours.
Option 1: (1)
Option 2: (2)
Option 3: (3)
Option 4: (4)
Correct Answer: (2)
Solution : The error lies in the second option.
The word much is used to refer to a large quantity or degree of something. In positive statements, especially when discussing a large quantity of something, it's more appropriate to use a lot of or lots of.
Question : If $B:A = 2:3$ and $A:C = 5:7$, then what is $(A + B):(B + C)$?
Option 1: $25:26$
Option 2: $25:36$
Option 3: $25:31$
Option 4: $27:43$
Correct Answer: $25:31$
Solution : $B:A = 2:3$ -----------(1) $A:C = 5:7$ -----------(2) Multiply equation (1) by 5 and equation (2) by 3, we have: $B:A = 10:15$ $A:C = 15:21$ ⇒ $B:A: C = 10:15:21$ Let $B=10k,A=15k,$ and $C=21k$ So, $(A + B):(B + C) = (15k + 10k):(10k
Question : If $\operatorname{cosec} A+\cot A=3$, $0 \leq A \leq 90^{\circ}$, then find the value of cos A.
Option 1: $\frac{3}{4}$
Option 2: $\frac{2}{5}$
Option 3: $\frac{3}{5}$
Option 4: $\frac{4}{5}$
Correct Answer: $\frac{4}{5}$
Solution : Given, $\operatorname{cosec} A+\cot A=3$ ⇒ $\frac{1}{\sin A}+\frac{\cos A}{\sin A}=3$ ⇒ $1+\cos A = 3\sin A$ We know, $\sin^2A+\cos^2A=1$ ⇒ $1+\cos A = 3\sqrt{1-\cos^2A}$ Squaring both sides, ⇒ $(1+\cos A)^2=9(1-\cos^2A)$ ⇒ $1+\cos^2 A+2\cos A=9-9\cos^2A$ ⇒ $10\cos^2A+2\cos A-8=0$ ⇒ $5\cos^2A+\cos A - 4=0$ ⇒ $5\cos^2A+5\cos A-4\cos A
The Question containing Inaapropriate or Abusive Words
Question lacks the basic details making it difficult to answer
Topic Tagged to the Question are not relevant to Question
Question drives traffic to external sites for promotional or commercial purposes
The Question is not relevant to User
And never miss an important update
