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Question : If $\frac{1}{2} $ is added to a number and the sum is multiplied by 3, the result is 21. Then the number is:
Option 1: 6.5
Option 2: 5.5
Option 3: 4.5
Option 4: –6.5
Correct Answer: 6.5
Solution : Let the number be $x$. According to the question, $(x + \frac{1}{2})\times 3=21$ ⇒ $(x + \frac{1}{2}) =\frac{21}{3}=7$ ⇒ $x =7- \frac{1}{2}$ $\therefore x =6.5$ Hence, the correct answer is 6.5.
Question : If $2(x^{2}+\frac{1}{x^{2}})-(x-\frac{1}{x})-7=0$, then two values of $x$ are:
Option 1: $1, 2$
Option 2: $2,-\frac{1}{2}$
Option 3: $0, 1$
Option 4: $\frac{1}{2},1$
Correct Answer: $2,-\frac{1}{2}$
Solution : Given: $2(x^{2}+\frac{1}{x^{2}})-(x-\frac{1}{x})-7=0$ We know that, $x^{2}+\frac{1}{x^{2}} = (x-\frac{1}{x})^2+2$ ⇒ $2[(x-\frac{1}{x})^2+2]-(x-\frac{1}{x})-7=0$ Put $x-\frac{1}{x}=t$ ⇒ $2t^2+4-t-7=0$ ⇒ $2t^2-t-3=0$ ⇒ $2t^2-3t+2t-3=0$ ⇒ $t(2t-3)+1(2t-3)=0$ ⇒ $(2t-3)(t+1)=0$ $\therefore t=\frac{3}{2}$ or, $ -1$ Now if, $x-\frac{1}{x}=\frac{3}{2}$ ⇒ $2x^2-2=3x$ ⇒ $2x^2-3x-2=0$ ⇒ $2x^2-4x+x-2=0$ ⇒ $2x(x-2)+1(x-2)=0$ ⇒ $(x-2)(2x+1)=0$ $\therefore x = 2$ or,
Question : Which Indian scientist has been chosen for the first 2022 Sheikh Saud International Prize for Materials Research by the Centre for Advanced Materials of the UAE?
Option 1: Ashok Sen
Option 2: Jayant Narlikar
Option 3: Raghunath Anant Mashelkar
Option 4: C. N. R. Rao
Correct Answer: C. N. R. Rao
Solution : The correct option is C. N. R. Rao.
Renowned Indian scientist Professor C. N. R. Rao, affiliated with the Jawaharlal Nehru Centre for Advanced Scientific Research in Bangalore, was honoured with the inaugural 2022 Sheikh Saud International Prize for Materials Research.
Question : Directions: Select the letter cluster from among the given options that can replace the question mark (?) in the following series. MN, NM, OL, PK, ?
Option 1: LQ
Option 2: QJ
Option 3: KJ
Option 4: JK
Correct Answer: QJ
Solution : Given: MN, NM, OL, PK, ?
The pattern is as follows – First letter of the series→M + 1 = N; N + 1 = O; O + 1 = P; P + 1 = Q Second letter of the series→N – 1 = M;
Question : Directions: In the following question, some parts of the sentence have errors, and some are correct. Find out which part of the sentence has an error. The number of that part is the answer. If a sentence is error-free, your answer is "No Error".
We must go (1)/ and congratulate him for (2)/ his brilliant success. (3)/ No Error (4)
Option 1: 1
Option 2: 2
Option 3: 3
Option 4: 4
Correct Answer: 2
Solution : The second part of the sentence has an error.
Note that "for" should be replaced with the preposition "on" to correctly convey the idea of congratulating someone for their achievement.
The correct sentence should be: "We must go and congratulate him on his brilliant success."
Question : What is the greatest number which divides 784 and 857 and leaves the remainder 4 and 2, respectively?
Option 1: 3
Option 2: 5
Option 3: 30
Option 4: 15
Correct Answer: 15
Solution : The number that divides 784 and leaves a remainder of 4 = 784 – 4 = 780 The number that divides 857 and leaves a remainder of 2 = 857 – 2 = 855 The greatest number that divides both 780 and 855 is their
Question : Directions: In the question, a part of the sentence is in bold. Below are given alternatives to the bold part at (1), (2), and (3) that may improve the sentence. Choose the correct alternative. In case no improvement is needed, your answer is (4).
I could not help to laugh at the joke.
(1) Laughing
(2) Laugh
(3) To laughing
(4) No Improvement
Option 1: (1)
Option 2: (2)
Option 3: (3)
Option 4: (4)
Correct Answer: (1)
Solution : The sentence can be improved using the first option.
The verb help is typically followed by a gerund (-ing form of a verb) when it is used to express that someone can't avoid or refrain from doing something. In this context, the action is laughing,
Question : What is the name of the book written by Panini?
Option 1: Mahabhashya
Option 2: Mitakshara
Option 3: Madhyamika Karika
Option 4: Ashtadhyayi
Correct Answer: Ashtadhyayi
Solution : The correct answer is Ashtadhyayi.
The grammar of classical Sanskrit was established by this work. Each of its eight parts is divided into quarter sections. Panini's most notable composition is titled Astadhyayi or Astaka. In this work, Panini distinguishes between the common language of
Question : If two LED TVs and one mobile phone cost INR 31,000, while two mobile phones and one LED TV cost INR 35,000, then the value of one mobile phone is:
Option 1: INR 13,500
Option 2: INR 12,500
Option 3: INR 13,000
Option 4: INR 12,000
Correct Answer: INR 13,000
Solution : Let $x$ be the cost of an LED TV and $y$ be the cost of a mobile phone. $2x + y = 31000$ ------------(i) $x + 2y = 35000$ ⇒ $x = 35000 – 2y$ ------------(ii) Substituting (ii) in (i), $2(35000 - 2y) +
Question : Four sentences are given, out of which three have spelling errors. Choose the sentence with all the correctly spelt words.
Option 1: They were meant, she says, to be "a public display of your allegaince."
Option 2: They fly around like nobody 's buisness.
Option 3: They also show problem behaviours, like physical aggression and cheating.
Option 4: This guide offers sugestions of capital interest to travelers.
Correct Answer: They also show problem behaviours, like physical aggression and cheating.
Solution : The correct choice is the third option.
Explanation: In this sentence, all the words are correctly spelled. The words behaviours, aggression, and suggestions are spelled according to British English spelling.
So, the correct sentence would
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