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Question : Directions: Which of the following letters will replace the question mark (?) and complete the letter series? J, D, X, R, L, ?
Option 1: F
Option 2: D
Option 3: E
Option 4: G
Correct Answer: F
Solution : Given: J, D, X, R, L, ?
Subtract 6 from the place value of each letter to get the required missing letter. J – 6 = D, D – 6 = X, X – 6 = R, R – 6 = L, L – 6
Question : Directions: A series is given below with one term missing. Choose the correct alternative from the given ones that will complete the series. GD, DI, AP, XY, ?
Option 1: UH
Option 2: IU
Option 3: ST
Option 4: UJ
Correct Answer: UJ
Solution : Given: GD, DI, AP, XY, ?
Subtract 3 from the positional value of the first letter and add consecutive odd numbers starting from 5 in increasing order to the positional value of the second number, to get the required missing term – GD→G – 3
Question : Select the option that can be used as a one-word substitute for the given group of words.
The expression of a wish that misfortune or doom befall a person
Option 1: Curse
Option 2: Praise
Option 3: Blessing
Option 4: Oath
Correct Answer: Curse
Solution : The first option is correct.
Curse means a word or words expressing a wish that something terrible will happen to somebody.
So, it is clear that curse can be used as a one-word substitute for the expression of a wish that misfortune or doom befall
Question : Directions: In this question, a part of the sentence is in bold. Below are given alternatives to the bold part at (1), (2), and (3) which may improve the sentence. Choose the correct alternative in case no improvement is needed your answer is (4).
Last evening I went to the optician and bought spectacles.
Option 1: 1
Option 2: 2
Option 3: 3
Option 4: 4
Correct Answer: 3
Solution : The correct choice for the sentence is the third option.
"A pair of spectacles" is used because the two lenses that make up the glasses are meant to be used together.
So, the correct sentence should be: Last evening I went to the optician and
Question : Which of the following Stupa sites is not located in Uttar Pradesh?
Option 1: Dhamek
Option 2: Ramabhar
Option 3: Chaukhandi
Option 4: Bharhut
Correct Answer: Bharhut
Solution : The correct option is Bharhut.
The state of Uttar Pradesh does not contain Bharhut. Bharhut is a historic location renowned for its archaeological artefacts, especially the Bharhut Stupa, which is well-known for its elaborately carved railings that portray various episodes from the life of
Question : Dr. APJ Abdul Kalam, a famous Indian scientist, autobiography is known as_______.
Option 1: One Life is Not Enough
Option 2: Wings of Fire
Option 3: Waiting for a Visa
Option 4: The Race of My Life
Correct Answer: Wings of Fire
Solution : The correct answer is Wings of Fire.
Dr. APJ Abdul Kalam was the former President of India and was also known as the Missile Man of India. He served as the 11th president from 2002 to 2007. He was born in Rameshwaram,
Question : Find the area of the rhombus whose diagonals are 16 cm and 20 cm.
Option 1: 110 cm2
Option 2: 150 cm2
Option 3: 160 cm2
Option 4: 120 cm2
Correct Answer: 160 cm2
Solution : $D_1$ = 16 cm $D_1$ = 20 cm Area of rhombus = $\frac{1}{2}D_1D_2=\frac{1}{2}×16×20=160\;cm^2$ Hence, the correct answer is 160 cm2.
Question : An article was sold for INR 98,496 after providing three successive discounts of 10%, 5%, and 4% respectively on the marked price. What was the marked price?
Option 1: INR 1,20,000
Option 2: INR 1,10,700
Option 3: INR 1,20,200
Option 4: INR 1,20,500
Correct Answer: INR 1,20,000
Solution : For three successive discounts of 10%, 5%, and 4%, Selling price = $\frac{100-\text{Discount}_1\%}{100}× \frac{100-\text{Discount}_2\%}{100}×\frac{100-\text{Discount}_3\%}{100}×$ marked price $⇒ 98496=\frac{100-10}{100}×\frac{100-5}{100}×\frac{100-4}{100}×$ marked price $⇒ 98496=\frac{90}{100}×\frac{95}{100}×\frac{96}{100}×$ marked price $\therefore$ Mrked price $= 120000$ Hence, the correct answer is INR 1,20,000.
Question : A boy increases his speed to $\frac{9}{5}$th times of his original speed. By doing this, he reaches his school 40 minutes before the usual time. How much time (in minutes) does he usually take?
Option 1: 120
Option 2: 30
Option 3: 90
Option 4: 45
Correct Answer: 90
Solution : Let the speed of the boy be $x$ km/hr. Initial time = $t$ So, distance = $tx$ New time = $t-40$ New speed = $x × (\frac{9}{5})=\frac{9x}{5}$ According to the question, $tx=(t-40)\frac{9x}{5}$ $⇒5t=9t-360$ $⇒ 4t=360$ $\therefore t =90$ minutes Hence, the correct answer is 90.
Question : A class has five sections that have 25, 30, 40, 45, and 60 students, respectively. The pass percentages of these sections are 20%, 30%, 35%, 40%, and 100% respectively. The pass percentage of the entire class is:
Option 1: 87%
Option 2: 63%
Option 3: 53%
Option 4: 79%
Correct Answer: 53%
Solution : Total number of students = 25 + 30 + 40 + 45 + 60 = 200 Number of students pass in Section A = 25 × $\frac{20}{100}$ = 5 The number of students passed in Section B = 30 × $\frac{30}{100}$ = 9 The number
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