Question : $\tan 4384^{\circ}+\cot 6814^{\circ}=?$
Option 1: – 1
Option 2: 2
Option 3: 0
Option 4: 1
New: SSC CGL 2025 Tier-1 Result
Latest: SSC CGL complete guide
Suggested: Month-wise Current Affairs | Upcoming Government Exams
Correct Answer: 0
Solution :
Given: $\tan 4384^{\circ}+\cot 6814^{\circ}$
= $\tan(360^{\circ}\times 12+64^{\circ})+\cot(360^{\circ}\times 19-26^{\circ})$
= $\tan64^{\circ}-\cot 26^{\circ}$
= $\tan64^{\circ}-\cot (90^\circ-64^{\circ})$
= $\tan64^{\circ}-\tan 64^{\circ}$
= $0$
Hence, the correct answer is 0.
Related Questions
Know More about
Staff Selection Commission Combined Grad ...
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Get Updates BrochureYour Staff Selection Commission Combined Graduate Level Exam brochure has been successfully mailed to your registered email id “”.




