Question : $\sqrt{\frac{1+\sin A}{1-\sin A}}=$_______.
Option 1: $\operatorname{coesc} A-\cot A$
Option 2: $\sec A-\tan A$
Option 3: $\sec A+\tan A$
Option 4: $\sec A$
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Correct Answer: $\sec A+\tan A$
Solution :
$\sqrt{\frac{1+\sin A}{1-\sin A}}$
$=\sqrt{\frac{1+\sin A}{1-\sin A}\times\frac{1+\sin A}{1+\sin A}}$
$=\sqrt{\frac{(1+\sin A)^2}{(1+\sin A)(1-\sin A)}}$
$=\sqrt{\frac{(1+\sin A)^2}{(1-\sin^2 A)}}$
$=\sqrt{\frac{(1+\sin A)^2}{(\cos^2 A)}}$
$=\frac{1+\sin A}{\cos A}$
$=\frac{1}{\cos A}+\frac{\sin A}{\cos A}$
$=\sec A+\tan A$
Hence, the correct answer is $\sec A+\tan A$.
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