Question : $\cos^3 60°-\cos^3 240°-\cos^3 360°=$ _________.
Option 1: $-\frac{3}{4}$
Option 2: $-\frac{7}{5}$
Option 3: $-\frac{3}{5}$
Option 4: $-\frac{9}{7}$
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Correct Answer: $-\frac{3}{4}$
Solution :
Given: $\cos ^3 60°-\cos ^3 240°-\cos ^3 360°$
Now, $\cos60°=\frac{1}{2}$
$\cos240°=\cos(180°+60°)=-\cos60°=-\frac{1}{2}$
$\cos360°=\cos(360°+0°)=\cos0°=1$
So, $\cos^3 60°-\cos^3 240°-\cos^3 360°$
= $(\frac{1}{2})^3-(-\frac{1}{2})^3-(1)^3$
= $\frac{1}{8}+\frac{1}{8}-1$
= $-\frac{3}{4}$
Hence, the correct answer is $-\frac{3}{4}$.
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