Question : (91 + 92 + 93 + ... + 110) is equal to:
Option 1: 4020
Option 2: 2010
Option 3: 6030
Option 4: 8040
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Correct Answer: 2010
Solution :
First term, $a$ = 91
Last term, $l$ = 110
Number of terms, $n$ = 20
The sum of n terms of series = $\frac{n}{2}(a+l)$
The sum of 20 terms of series = $\frac{20}{2}(91+110)=10(91+110)=2010$
Hence, the correct answer is 2010.
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