a 68.5 g sample of the hydrated Sr(OH)2.xH20 dried in an oven to give 3.13 g of anhydrous Sr(OH)2.what is the value of x?
Answer (1)
22nd Dec, 2019
Hello,
To find the value of x you should start with the following steps
a) First you need to calculate the mass and moles of H2O i.e.
6.85 g - 3.13 g = 3.72 g H2O / 18.0 g/mol = 0.207 moles H2O
b) Now calculate moles Sr(OH)2 remaining:
3.13 g Sr(OH)2 / 121.6 g/mol = 0.0257 moles Sr(OH)2
c) Lastly calculate the ratio of moles H2O / moles Sr(OH)2:
0.207 / 0.0257 = 8.0
and finally the value of x comes out to be
8.0
.
Hope this helps.
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