A Carnot cycle operating at T1 = 500 K and T2 = 300 K generates approximately 2kJ of mechanical effort each cycle. How much heat is transmitted to the engine by the reservoirs?
Answer (1)
5th Nov, 2021
Efficiency of carnot engine formula of a Carnot engine η = 1 - (T2 / T1)
T1 = 500 K
T2 = 300 K
η = 1 - (300 / 500) = .4
Also, η = Output work / Heat Supplied = 2000 / x
Now, 2000 / x = .4
Thus, x = 5000J
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