a cube of side 4 cm and mass 50g is placed in a liquid of density 1.2g/cm3. find the height of the cube remaining outside the liquid
Answer (1)
Hii
According to querry-
Let weight of block be-mg
And let upthrust applied will be Vpg. And rest of part will be floating above. So,
Vpg=mg
V=m/p and the submerged volume will be-4*4*h
On solving h will be equal to 2.6 and so the floating height will be 1.4 cm.
Where m is mass, p is density of liquid
Hope it helps
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