Question : A hemispherical bowl has a radius of 7 cm. It is to be painted from inside as well as outside. Find the cost of painting it at the rate of Rs. 40 per 20 cm2. (Take the thickness of the bowl as negligible).
Option 1: Rs. 1,232
Option 2: Rs. 1,125
Option 3: Rs. 1,432
Option 4: Rs. 1,550
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Correct Answer: Rs. 1,232
Solution :
The radius of the hemispherical bowl = 7 cm.
Curved surface area = $2\pi r^2$
Inner and outer surface area of the bowl = $2×2\pi r^2$ = $4\pi r^2$
= $4×\frac{22}{7}×7×7$
= 616 cm
2
Total cost of painting at the rate of Rs. 40 per 20 cm
2
= $616 ×\frac{40}{20}$ = Rs. 1,232
Hence, the correct answer is Rs. 1,232.
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