Question : A man starts from place A and reaches place B in 50 hours. He travels $\frac{1}{4}$th distance at the speed of 5 km/hr and the remaining distance at the speed of 15 km/hr. What is the distance between A and B?
Option 1: 525 km
Option 2: 500 km
Option 3: 375 km
Option 4: 425 km
Correct Answer: 500 km
Solution :
Let the distance between A and B be $4x$ km.
⇒ Distance covered with speed 5 km/hr = $\frac14 × 4x = x$
⇒ Time taken = $\frac{\text{distance}}{\text{speed}} = \frac{x}{5}$
⇒ Remaining distance $=4x - x = 3x$
⇒ Time taken = $\frac{\text{distance}}{\text{speed}} = \frac{3x}{15}$
⇒ Total time $=\frac{x}{5} + \frac{3x}{15}= \frac{3x+3x}{15}= \frac{6x}{15}=\frac{2x}{5}$
According to the question,
$\frac{2x}{5} = 50$
⇒ $x = 125$
$\therefore$ Total distance = $4x = 4 × 125= 500$ km
Hence, the correct answer is 500 km.
Related Questions
Know More about
Staff Selection Commission Multi Tasking ...
Application | Cutoff | Selection Process | Preparation Tips | Eligibility | Exam Pattern | Admit Card
Get Updates Brochure
Your Staff Selection Commission Multi Tasking Staff Exam brochure has been successfully mailed to your registered email id “”.
