A motor has an electrical input of 30KJ and is used to raise a 100kg load to a height of 25m when fitted to a crane winch.The efficiency of the winch is(g=10ms-2)
Answer (1)
m = 100 kg
g = 10 m/s
h = 25 m
Input Energy =30,000 J
Output Energy =m *g*h
=100 * 25 * 10
= 25000 J
Efficiency = Output Energy /Input Energy
= 25000/30000
= 5 /6 Ans.
Since some energy is lost in the form of heat energy , therefore efficiency is less than one.
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