a parallel plate condenser has two circular metal plates of radius 10cm at adistance the condenser being charged with electric field at rate5* 10000000000000 the displacement current

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Radius of circular plate=r=2cm=0.02m

distance between the plates=d=0.1mm=0.1*10^-3m

the change in potential difference between the plates dV/dt=5*10^13vs

Permitivity of free space=eo=8.85*10^-12 C^2N^-1m^-2

Hence area of the each plate,A=πr^2

=π (0.02)^2

=1.26*10^-3 m^2--------------------1

we know,C=eoA/d

C=8.85*10^-12*1.26*10^-3/0.1*10^-3

C=11.15*10^-11 F

displacement current=Id=C.dV/dt

Id=11.15*10^-11*5*10^13

Id=57.55*10^2 A

Hope it helps!!!!

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