Question : A person has three iron bars whose lengths are 20, 30 and 40 metres, respectively. He wants to cut pieces of the same length from each of the three bars. What is the least number of total pieces if he cuts without any wastage?
Option 1: 8
Option 2: 10
Option 3: 9
Option 4: 11
Correct Answer: 9
Solution :
HCF of 20, 30 and 40 = 10
Number of pieces from 20m long iron bar = $\frac{20}{10} = 2$
Number of pieces from 30m long iron bar = $\frac{30}{10} = 3$
Number of pieces from 40m long iron bar = $\frac{40}{10} = 4$
Total number of pieces = 2 + 3 + 4 = 9
Hence, the correct answer is 9.
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