A wire is suspended vertically from one of its end is stretched by attaching a weight of 200N to the lower end. The weight strectchs the
Answer (1)
Hello Shreyas,
We know that, U=(1/2)FΔL(This is the relation for streched wire potential energy)
U=1/2 x 200 x 10^-3
U=0.1 J
Hope this helps and all the very best to you!
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