age of the father is 30 years more than his son after 5 years the product of their ages become 400 find the present age of the both son and father
Hello aspirant,
Let the son's present age be x. Then the father's age is x+30.
After 5 years :
Son = x+5, Father = (x+35)
Their product is 400:
(x+5)(x+35) = 400
x^2 + 40x +175 =400
x^2+40x-225 = 0
Solving gives x=5.
So the son is 5 years old and the father is 35 years old.
FOR REFERENCE : https://school.careers360.com/articles/math-question-solver
Hope the details will help you.
THANK YOU
Hello aspirant,
Let the son's present age be x. Then the father's age is x+30.
After 5 years :
Son = x+5, Father = (x+35)
Their product is 400:
(x+5)(x+35) = 400
x^2 + 40x +175 =400
x^2+40x-225 = 0
Solving gives x=5.
So the son is 5 years old and the father is 35 years old.
FOR REFERENCE : https://school.careers360.com/articles/math-question-solver
Hope the details will help you.
THANK YOU
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