Question : Ashok runs $2 \frac{2}{3}$ times as fast as Bharat. If Ashok gives Bharat a head start of 160 m, then how far must the winning post be so that Ashok and Bharat can reach it at the same time?
Option 1: 225 m
Option 2: 256 m
Option 3: 240 m
Option 4: 200 m
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Correct Answer: 256 m
Solution :
The ratio of speeds of Ashok and Bharat = $2\frac{2}{3}:1= 8:3$
That means in a race of 8 m, Ashok gains 5 m over Bharat.
⇒ 160 m will be gained by Ashok in a race of $\frac{8}{5}\times 160 = 256 \ \mathrm{m}$
Hence, the correct answer is 256 m.
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