can i get admission in any NIT with 93.03 percentile in JEE PAPER 2 with 66% in class 12th?
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Hello aakansha
By calculating your rank using rank predictor formula given below:
Rank predictor formula=(100-percentile)/100*n,here n is total number of students who have attended jee mains in 2019 which is 965000
Your rank will be 67260,with this rank it is tough to get into any of the NIT's,you can check the 2019 cutoffs for NIT's in the link mentioned below.
https://engineering.careers360.com/articles/nits-cutoff-for-top-btech-branches
If you have any questions further feel free to ask.
Thank you
Team Careers.
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