can I get seat in varangal nit college with 86.6% please tell about this and iam from general obc categories
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Hello,
You can expect your rank to be around 116447 and the formula to calculate is (100-your total percentile)*869010/100
Where 869010 is that total number of candidates appeared in JEE Main January session. Now the cut off depends on number of candidates appeared, difficulty of exam etc. In 2019 the cu toff was as follows
- EEE: 11835
- MME: 23966
- Mech: 18474
- ECE: 8838
- CSE: 4632
- Civil : 17428
- Chemical: 27770
- Biotechnology: 27626
Considering previous year cut off and with this rank you cannot get admission in NIT, Warangal. You need to score minimum 97 percentile to get seat in this NIT
You can predict the colleges using our JEE Main predictor tool
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