Question : Determine the value of $x$, if $x = \frac{(943+864)^2-(943-864)^2}{(1886\times1728)}$.
Option 1: 1
Option 2: 4
Option 3: 79
Option 4: 1789
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Correct Answer: 1
Solution :
Given:
$x = \frac{(943+864)^2-(943-864)^2}{(1886\times1728)}$
This can be simplified using the identity $(a+b)^2 - (a-b)^2 = 4ab$, where $a = 943$ and $b = 864$.
⇒ $x = \frac{4×943×864}{1886\times1728}$
⇒ $x = \frac{2×943×2×864}{1886\times1728}$
⇒ $x=1$
Hence, the correct answer is $1$.
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