Question : Directions: Choose one of the following correct combinations of mathematical signs that can be filled sequentially to balance the following equation.
Option 1: ÷, ×, –, =, ×
Option 2: ÷, ×, =, +, +
Option 3: ÷, ×, +, =, –
Option 4: +, =, ÷, ×, +
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Correct Answer: ÷, ×, +, =, –
Solution :
Given:
Let's check the given options –
First option:
÷, ×, –, =, ×
⇒ 28 ÷ 4 × 3 – 9 = 42 × 12
Solving the L.H.S. of the equation –
= 28 ÷ 4 × 3 – 9
= 7 × 3 – 9
= 21 – 9 = 12
Solving the R.H.S. of the equation –
= 42 × 12 = 504
12 ≠ 504
Second option:
÷, ×, =, +, +
⇒ 28 ÷ 4 × 3 = 9 + 42 + 12
Solving the L.H.S. of the equation –
= 28 ÷ 4 × 3
= 7 × 3 = 21
Solving the R.H.S. of the equation –
= 9 + 42 + 12 = 63
21 ≠ 63
Third option:
÷, ×, +, =, –
⇒ 28 ÷ 4 × 3 + 9 = 42 – 12
Solving the L.H.S. of the equation –
= 28 ÷ 4 × 3 + 9
= 7 × 3 + 9
= 21 + 9 = 30
Solving the R.H.S. of the equation –
= 42 – 12 = 30
L.H.S. = R.H.S.
Fourth option:
+, =, ÷, ×, +
28 + 4 = 3 ÷ 9 × 42 + 12
Solving the L.H.S. of the equation –
= 28 + 4
= 32
Solving the R.H.S. of the equation –
= 0.33 × 42 + 12
= 13.86 + 12 = 25.86
32 ≠ 25.86
So, only the third option satisfies the equation. Hence, the third option is correct.
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