Question : Directions: In a certain code language, LED is coded as 1587 and BAN is coded as 5417. What will be the code for HIT in the given code language?
Option 1: 111223
Option 2: 101233
Option 3: 121144
Option 4: 101212
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Correct Answer: 111223
Solution :
Given:
LED is coded as 1587 and BAN is coded as 5417.
Add 3 to the positional value of letters of LED, to obtain the code –
L→12; E→5; D→4
L→12 + 3 = 15; E→5 + 3 = 8; D→4 + 3 = 7
Thus, LED is coded as 1587.
And, BAN is coded as 5417 –
B→2; A→1; N→14
B→2 + 3 = 5; A→1 + 3 = 4; N→14 + 3 = 17
Thus, BAN is coded as 5417.
Similarly, follow the same pattern for HIT –
H→8; I→9; T→20
H→8 + 3 = 11; I→9 + 3 = 12; T→20 + 3 = 23
Thus, HIT is coded as 111223. Hence, the first option is correct.
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