Question : Directions: In the following question, identify the odd letter cluster from the given alternatives.
Option 1: CXA
Option 2: MNQ
Option 3: PKN
Option 4: HSU
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Correct Answer: HSU
Solution :
Let's check the options –
First option:
CXA; C + X = 3 + 24 = 27; X + 3 = A
Second option:
MNQ; M + N = 13 + 14 = 27; N + 3 = Q
Third option:
PKN; P + K = 16 + 11 = 27; K + 3 = N
Fourth option:
HSU; H + S = 8 + 19 = 27; S +
2 = U
So, the fourth option is different from the other options. Hence, the fourth option is correct.
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