Question : Directions: Select the combination of letters that when sequentially placed in the blanks of the given letter series will complete the series.
ab_eea_bc_eaaa_cee
Option 1: aecc
Option 2: caeb
Option 3: caec
Option 4: ccae
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Correct Answer: caeb
Solution :
Given:
ab_eea_bc_eaaa_cee
First, divide the series into parts→ab_ee / a_bc_e / aaa_cee
Let's check the given options –
First option:
aecc; ab
a
ee / a
e
bc
c
e / aaa
c
cee (No repeated pattern found.)
Second option:
caeb; ab
c
ee / a
a
bc
e
e / aaa
b
cee (The occurrence of the letter a is increased by 1 and bcee is repeated.)
Third option:
caec; ab
c
ee / a
a
bc
e
e / aaa
c
cee (No repeated pattern found.)
Fourth option:
ccae; ab
c
ee / a
c
bc
a
e / aaa
e
cee (No repeated pattern found.)
So, the series becomes→abceeaabceeaaabcee. Hence, the
second option
is correct.
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