Question : Directions: Select the option that is related to the fifth alphanumeric cluster in the same way as the second alphanumeric cluster is related to the first alphanumeric cluster and the fourth alphanumeric cluster is related to the third alphanumeric cluster.
I81: K121 :: D16 : F36 :: O225 : ?
Option 1: P256
Option 2: P265
Option 3: Q289
Option 4: R324
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Correct Answer: Q289
Solution :
Given:
I81: K121 :: D16 : F36 :: O225 : ?
Add 2 in the positional value of the alphabet to obtain the next cluster alphabet and the number is the square of the positional value of the alphabet.
I81: K121→ I; The positional value of I is 9; A square of 9 is 81 = I81→ I + 2 = K; The positional value of K is 11; A square of 11 is 121 = K121
D16: F36→ D; The positional value of D is 4; A square of 4 is 16= D16→D + 2 = F; The positional value of F is 6; A square of 6 is 36 = F36
Similarly, O225: ?→O; The positional value of O is 15; A Square of 15 is 225= O15→O + 2 = Q; The positional value of Q is 17; A square of 17 is 289 = Q289
So, the required term is Q289. Hence, the third option is correct.
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