Question : Due to inclement weather, an aeroplane reduced its speed by 300 km/h and reached its destination of 1200 km late by 2 hours. Then, the scheduled duration of the flight was:
Option 1: 1 hour
Option 2: 1.5 hours
Option 3: 2 hours
Option 4: 2.5 hours
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Correct Answer: 2 hours
Solution :
Let the original speed of the aeroplane be $x$ km/h.
According to the question,
$\frac{1200}{x–300} – \frac{1200}{x} = 2$
⇒ $\frac{1200}{x–300} – \frac{1200}{x} = 2$
⇒ $1200(\frac{x–x+300}{x(x–300)}) = 2$
⇒ $1200(\frac{300}{x(x–300)}) = 2$
⇒ $x(x–300) = 600(300)$
⇒ $x(x–300) = 600(600–300)$
⇒ $x = 600$
Hence, the scheduled duration of the flight was $\frac{1200}{600} = 2$ hours.
Hence, the correct answer is 2 hours.
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