Question : Find the mean proportion of $\frac{a^3+b^3}{a-b}$ and $\frac{a^2-b^2}{a^2-a b+b^2}$.
Option 1: $1$
Option 2: $a+b$
Option 3: $\frac{a+b}{a-b}$
Option 4: $\sqrt{a+b}$
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Correct Answer: $a+b$
Solution :
Let the mean proportion be $x$.
So, $x= \sqrt{\frac{a^3+b^3}{a-b}\times \frac{a^2-b^2}{a^2-a b+b^2}}$
⇒ $x= \sqrt{\frac{(a+b)(a^2-a b+b^2)}{a-b}\times \frac{(a-b)(a+b)}{a^2-a b+b^2}}$
⇒ $x=a+b$
Hence, the correct answer is $a+b$.
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