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for the g. p. if r=1/3,a=3 find t7

siddharth admane 4th Dec, 2019

Answers (2)

Avishek Dutta 4th Dec, 2019

Now let a,ar,ar^2,..... be a gp.the first term is a and common ratio is r.
Now the nth term of the gp is
t(n)=ar^(n-1)
Now we are given that a= 3
And r=1/3.
Then t(7)=ar^6
=3*(1/3^6)
=3/729
=1/243

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ADITYA KUMAR Student Expert 4th Dec, 2019

Hello there!

Greetings!

It's simple formula based question;

We have

a=3,r=1/3, and we have to find t7

We know that ,tn =ar^n-1

Then ,t7=3(1/3)^6

t7=3(1/729)

t7=1/243.

Thus, t7 = 1/243

Thankyou

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