for the g. p. if r=1/3,a=3 find t7
Answers (2)
Now let a,ar,ar^2,..... be a gp.the first term is a and common ratio is r.
Now the nth term of the gp is
t(n)=ar^(n-1)
Now we are given that a= 3
And r=1/3.
Then t(7)=ar^6
=3*(1/3^6)
=3/729
=1/243
Now the nth term of the gp is
t(n)=ar^(n-1)
Now we are given that a= 3
And r=1/3.
Then t(7)=ar^6
=3*(1/3^6)
=3/729
=1/243
Comments (0)
Hello there!
Greetings!
It's simple formula based question;
We have
a=3,r=1/3, and we have to find t7
We know that ,tn =ar^n-1
Then ,t7=3(1/3)^6
t7=3(1/729)
t7=1/243.
Thus, t7 = 1/243
Thankyou
Greetings!
It's simple formula based question;
We have
a=3,r=1/3, and we have to find t7
We know that ,tn =ar^n-1
Then ,t7=3(1/3)^6
t7=3(1/729)
t7=1/243.
Thus, t7 = 1/243
Thankyou
Comments (0)




