How many 6-digit numbers are left if we subtract 50% of them?
Answer (1)
Total 6 digit numbers are 900000, On subtracting 50% of 900000, we get:
\begin{aligned}
&=900000\times(\frac{50}{100})\\
&=450000
\end{aligned}
Hence, a total of forty lakh, fifty thousand numbers are left when we subtract 50% of 900000
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