I got 90.01 percentile in my jee b-arch exam. I am an OBC student .What would be my score and my rank?
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hey Divya
According to careers360 prediction your rank will lie between 14000-15000. Also you can refer to the following link.....
https://engineering.careers360.com/articles/jee-main-paper-2-result
wish you luck
.
Firstly you have got very good percentile congrats!!!
It is difficult to predict the score as per the results only percentile score is released.you have to wait for official results.
Use this formula to predict the rank
.Rank Formula = (100 - your total score) X 145386 /100.
Your rank is 14538 this rank may differ from the official cutoff and results which were released on the month of April by national testing agency NTA officially.
.
On the basis of rank only the cutoff for college is decided
I will provide previous years cutoff of batch Colleges you can get an idea about cutoff:
.
https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning
.
If you have any questions further let me know.
.
Thank you!!!
hello divya
Well, it's very difficult as of now,to predict the cutoff for JEE mains paper 2 based on percentile.You can first calculate your rank by rank=(100-percentile)*874469.With this rank,you can compare previous year's cutoff for different colleges and can predict some of the colleges you may be getting.But remember this is not the final rank.It will change based on the april session of mains.Hope this helps.
Good Luck!
1 like
Reply
Hello Divya Sree,
You can use the formulae given below to calculate the rank -
Rank Formula = (100 - your total score) X 145386 /100.
145386 are the number of candidates appeared for the examination.
Hope this will help you!
All the best!
Thanku.
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