I got 90.99 percentile in jeemains 2019 (jan).Can anybody suggest me the best college with this percentile.And I am looking for govt college
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Answers (2)
25th Feb, 2019
Helloo...
The formula to calculate the approximate rank is :
(100-percentile)*874469/100.
If you apply your percentile in the formula your approximate rank will be around 78,789.
For this rank you will be having chances to get the seat in NIT. For more details about the closing ranks you can check the following link:
https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff
All the best..
The formula to calculate the approximate rank is :
(100-percentile)*874469/100.
If you apply your percentile in the formula your approximate rank will be around 78,789.
For this rank you will be having chances to get the seat in NIT. For more details about the closing ranks you can check the following link:
https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff
All the best..
Comments (0)
25th Feb, 2019
Hello Vaibhav,
You are getting 76500 rank as per our rank predictor formula.
Our rank predictor formula = ((100 - your percentile)/100)*Total number of candidate.
Total number of candidate = 850000 in Jan Jee main.
Your rank range from 74000- 78000.
With this percentile you can get GFTIs,CFTIs in your state with help of home state quota.
Chances of NIT are very less.
If you have any questions remain than comment below.
For more information regarding college tell your state.
Good luck...
You are getting 76500 rank as per our rank predictor formula.
Our rank predictor formula = ((100 - your percentile)/100)*Total number of candidate.
Total number of candidate = 850000 in Jan Jee main.
Your rank range from 74000- 78000.
With this percentile you can get GFTIs,CFTIs in your state with help of home state quota.
Chances of NIT are very less.
If you have any questions remain than comment below.
For more information regarding college tell your state.
Good luck...
Comments (0)
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