I got 97.66 percentile in JEE paper 2 can I get in an NIT I am OBC architecture please help
Latest: Free All-India JEE Main 2026 Mock Test - Attempt Now
JEE Main Sample Papers: Physics | Chemistry | Maths | Top 30 Repeated Questions
JEE Main QP & Mock: Previous 10 Year Questions | Chapter Wise PYQs | Mock test Series
JEE Main Most Scoring Concept: January 2025 Session | April 2025 Session | Overall
Hello
It is difficult to predict the actual rank or JEE Advanced qualifying marks as for the first time JEE Main is being conducted twice and rank will be based on NTA percentile score.
You may calculate your expected rank.
145386 are the number of candidates appeared for the JEE Main paper 2 January exam. So rank formula is (100- your total score) * 145386/ 100.
Your expected rank will be around 3402.
You can check the previous year cutoff for reference and to have an idea about the rank required for admission
https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning
Good Luck!
p { margin-bottom: 0.25cm; line-height: 120%; }a:link { }
Related Questions
Know More about
Joint Entrance Examination (Main)
Application | Eligibility | Preparation Tips | Question Paper | Admit Card | Answer Key | Result | Accepting Colleges
Get Updates Brochure
Your Joint Entrance Examination (Main) brochure has been successfully mailed to your registered email id “”.
.jpg)
