i have 71.89 percentile in jee so i am eligible to admission in nirma mechanical engineering department
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Answer (1)
30th Jun, 2020
Hello there,
According to the formula, [100-71.89*869010/100], your All India Rank is 244278 approximately. You haven't mentioned your category, so I'm assuming that you are from the general category. Analysing the previous year data, the cutoff rank for Mechanical Engineering in Nirma University was 29073. Hence it is quite difficult for you to get a seat there. Also, note that the cut-off rank changes every year depending on the difficulty of the paper, and the number of candidates appearing for it.
You can also use our college predictor:
Hope this answer helps you.
Good luck!!
According to the formula, [100-71.89*869010/100], your All India Rank is 244278 approximately. You haven't mentioned your category, so I'm assuming that you are from the general category. Analysing the previous year data, the cutoff rank for Mechanical Engineering in Nirma University was 29073. Hence it is quite difficult for you to get a seat there. Also, note that the cut-off rank changes every year depending on the difficulty of the paper, and the number of candidates appearing for it.
You can also use our college predictor:
Hope this answer helps you.
Good luck!!
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