Question : If $x-\frac{1}{x}$ = 13, what will be the value of $x^4+\frac{1}{x^4}$?
Option 1: 28561
Option 2: 29243
Option 3: 27887
Option 4: 29239
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Correct Answer: 29239
Solution :
$x-\frac{1}{x}=13$
$⇒(x-\frac{1}{x})^2=13^2$
$⇒x^2+\frac{1}{x^2}-2=169$
$⇒x^2+\frac{1}{x^2}=171$
$⇒(x^2+\frac{1}{x^2})^2=171^2$
$⇒x^4+\frac{1}{x^4}+2=29241$
$\therefore x^4+\frac{1}{x^4}=29239$
Hence, the correct answer is 29239.
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