if a=(1 2) b=(3 -2) and p moves in the plane such that ap+bp=7 then the locus of p has two axes of symmetry.their equations are
Answer (1)
1)The value of AB will be root(4+16) = root(20)
2)hence the equation will be (y-y1)=((y2-y1)/(x2-x1))*(x=x1)
3)Substituting the value you get y-2=(-4/2)*(x-1)
hence y-2=-2x+2-----(1)
4)Slope m2= 1/2
hence the other equation will be y-0=1/2(x-2) for point (2,0)
=x-2y-2=0
Comments (0)




