If aCosA = 1 and bSinA = 1 then TanA = ?
Answer (1)
7th Aug, 2021
Dear Student,
aCosA = 1
This implies Cos A = 1/a......................................................................(Equation1)
bSinA = 1
This implies Sin A = 1/b .........................................................................(Equation 2)
Tan A = Sin A/Cos A..............................................................................(Equation 3)
Therefore ,
From (1),(2) & (3)
we get,
Tan A = (1/b)/(1/a)
TanA = a/b
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