Question : If $M = 0.1 + (0.1)^2 + (0.01)^2$ and $N = 0.3 + (0.03)^2 + (0.003)^2$, then what is the value of $(M+ N)$?
Option 1: 0.411009
Option 2: 0.413131
Option 3: 0.313131
Option 4: 0.131313
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Correct Answer: 0.411009
Solution :
$M = 0.1 + (0.1)^2 + (0.01)^2$
$= 0.1 + 0.01 + 0.0001$
$= 0.1101$
$N = 0.3 + (0.03)^2 + (0.003)^2$
$= 0.3 + 0.0009 + 0.000009$
$= 0.300909$
We can add $M$ and $N$ to get the final result.
So, $M + N = 0.1101 + 0.300909 = 0.411009$
Hence, the correct answer is $0.411009$.
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