Question : If $b=5$, determine the value of an expression $\left(\frac{5}{b}+5b\right)\left(\frac{25}{b^{2}}-25+25 b^2\right)$ using an identity.
Option 1: 25,726
Option 2: 15,626
Option 3: 15,438
Option 4: 25,636
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Correct Answer: 15,626
Solution :
$(\frac{5}{b}+5 b)(\frac{25}{b^{2}}-25+25 b^2)$
This equation is in the form of $(x+y)(x^{2}–xy+y^{2})$
We know $x^{3}+y^{3}=(x+y)(x^{2}–xy+y^{2})$
So, $x = \frac{5}{b}$ and $y = 5b$
Putting the value of $b = 5$ we get,
$x^{3}+y^{3} = (\frac{5}{5})^{3} + (5\times 5)^{3}$
Or, $x^{3}+y^{3}= 1+15625 = 15626$
Hence, the correct answer is 15,626.
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