if I got 97marks in jee on 27th august2021 2nd shift. what is my percentile

Hello,

Based on Careers360 JEE Main rank predictor tool the overall percentile is expected to be in between 92.07 - 94.53 and the overall expected rank is in between 71610 - 80500 .To check the expected rank click on the link below

JEE Main Rank Predictor 2021 - Predict your JEE Main 2021 Rank, JEE Main Percentile Calculator

JEE Main Rank Predictor - Know your expected IIT JEE Main 2021 Rank by using Careers360 JEE Main rank predictor tool based on JEE Mains scor ...

Last year the cut off percentile was as follows

• General: 90.3765335
• EWS: 70.2435518
• OBC-NCL: 72.8887969
• SC: 50.1760245
• ST: 39.0696101
• PWD: 0.0618524

In 2021 the cut off percentile is expected to be as follows

• General 90-95
• EWS/OBC-NCL: 70-75
• SC: 50-55
• ST: 40-45
• PWD:1-2

Considering the previous year cut off you have decent chances to qualify in JEE Main and apply for JEE Advanced. Cut off depends on the total number of candidates appeared, difficulty level of examination and total number of seats available etc. It may increase or decrease depending on these factors.

Hey there

Your marks are very low and it is quite difficult to answer you question about the percentile.You can predict your college by clicking on the below link which has access to the college Predictor:

https://www.google.com/url?sa=t&source=web&rct=j&url=https://engineering.careers360.com/jee-main-college-predictor&ved=2ahUKEwiahKfk5-ryAhVnyTgGHZ3qDDgQtwJ6BAgLEAE&usg=AOvVaw1pTMu5LewXe0n3JPiA8V2U

Hey there

.You can predict your college by clicking on the below link which has access to the college Predictor:

https://www.google.com/url?sa=t&source=web&rct=j&url=https://engineering.careers360.com/jee-main-college-predictor&ved=2ahUKEwiahKfk5-ryAhVnyTgGHZ3qDDgQtwJ6BAgLEAE&usg=AOvVaw1pTMu5LewXe0n3JPiA8V2U

Hey there

You can predict your college by clicking on the below link which has access to the college Predictor:

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer