Question : If $\theta$ is an acute angle and $\cos \theta=\frac{39}{89}$, what is the value of $\sin \theta$ ?
Option 1: $\frac{49}{89}$
Option 2: $\frac{79}{89}$
Option 3: $\frac{80}{89}$
Option 4: $\frac{50}{89}$
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Correct Answer: $\frac{80}{89}$
Solution :
$\cos \theta=\frac{39}{89}=\frac{\text{Base}}{\text{Hypotenuse}}$
Perpendicular = $\sqrt{89^2-39^2}=\sqrt{(89-39)(89+39)}=\sqrt{50×128}=80$
So, $\sin \theta =\frac{\text{Perpendicular}}{\text{Hypotenuse}}= \frac{80}{89}$
Hence, the correct answer is $\frac{80}{89}$.
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