If m-n , m , m+n are the lengths of the sides of an obtuse angled triangle , then n lies in
Hello Aspirant...
Δ is obtused
greatest side will be m+n.
Smallest side will be m−n,
We know that , sum of two sides of a Δ is greater than 3rd side.
∴ m+m−n>m+n.
2m−n>m+n.
2m−m>n+n.
m>2n
or 2n<m
n< m/2.
I hope it helps.
Regards.




