Question : If the difference between the average of $x, y$ and $y, z$ is 12, then the difference between $x$ and $z$ is:
Option 1: 24
Option 2: 48
Option 3: 12
Option 4: 6
Correct Answer: 24
Solution :
Given: The difference between the average of $x$, $y$ and $y$, $z$ is 12.
According to the question,
$\frac{x+y}{2}–\frac{y+z}{2}=12$
⇒ $\frac{x+y–y–z}{2}=12$
⇒ $\frac{x–z}{2}=12$
⇒ $x–z=24$
Hence, the correct answer is 24.
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