Question : If the radius of a sphere is decreased by 48%, then by what percentage does its surface area decrease?
Option 1: 82.91%
Option 2: 72.96%
Option 3: 78.98%
Option 4: 86.26%
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Correct Answer: 72.96%
Solution :
Given: the radius of a sphere is decreased by 48%.
Let the radius be $r$, then the surface area of the sphere = $4\pi r^2$
Now the radius has decreased by 48%,
So, the radius = $r-0.48r$ = $0.52r$
And the new area = $4\pi (0.52r)^2$ = $4\pi r^2(0.2704)$
Therefore, the percentage decrease in surface area
= $\frac{4\pi r^2-4\pi r^2(0.2704)}{4\pi r^2}×100$
= $72.96\%$
Hence, the correct answer is 72.96%.
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