If the sum of three consecutive terms of on arithmetic progression is24 then second term

Hello Dhanya,

If three consecutive terms of an arithmetic progression are $a-d$, $a$, $a+d$, then:

$(a-d)+a+(a+d)=24$

$3a=24$

$\boxed{a=8}$

Therefore, the second term is $8$.

$$(a-d)+a+(a+d)=24$$ $$3a=24$$ $$\boxed{{\displaystyle a=8}}$$

Therefore, the second term is 8.