Question : If $x+\frac{1}{x}=7$, the value of $x^6+\frac{1}{x^6}$ is:
Option 1: 113682
Option 2: 103682
Option 3: 103882
Option 4: 103862
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Correct Answer: 103682
Solution :
Given: $x+\frac{1}{x}=7$
Squaring both sides, we get:
$(x+\frac{1}{x})^2=7^2$
⇒ $x^2+\frac{1}{x^2}+2×x×\frac{1}{x}=49$
⇒ $x^2+\frac{1}{x^2}=49-2$
⇒ $x^2+\frac{1}{x^2}=47$
Now, cubing both sides, we get:
⇒ $x^6+\frac{1}{x^6}+3×x^2×\frac{1}{x^2}(x^2+\frac{1}{x^2})=47^3$
⇒ $x^6+\frac{1}{x^6}+3×47=103823$
⇒ $x^6+\frac{1}{x^6}=103823-141$
⇒ $x^6+\frac{1}{x^6}=103682$
Hence, the correct answer is 103682.
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