Question : If $a=17, b=13$, then find the value of the expression $\left(a^3-b^3 – 3a^2b+3ab^2\right)$.
Option 1: – 64
Option 2: – 27000
Option 3: 27000
Option 4: 64
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Correct Answer: 64
Solution :
Given: $a=17, b=13$
So, $\left(a^3-b^3 – 3a^2b+3ab^2\right)$
= $a^3-b^3 – 3 ab(a–b)
= (a–b)^3$
= $(17–13)^3$
= 4
3
= 64
Hence, the correct answer is 64.
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