Question : If $\{(1÷x)×(x^3-2x^2)+(4^3÷2^5)×x\}÷25=1$, then the possible values of $x$ is/are:
Option 1: $-5$
Option 2: $5$
Option 3: $0$
Option 4: Both $5$ and $-5$
Answer (1)
24th Jan, 2024
Correct Answer: Both $5$ and $-5$
Solution :
$\{(1÷x)×(x^3-2x^2)+(4^3÷2^5)×x\}÷25=1$
⇒ $(x^2-2x)+2x=25$
⇒ $x^2=25$
$\therefore x=\pm5$
Hence, the correct answer is both $5$ and $–5$.
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