Question : If $\sqrt{5329}=73$, then the value of $\sqrt{5329}+\sqrt{53.29}+\sqrt{0.5329}+\sqrt{0.005329}+\sqrt{0.00005329}$ is:
Option 1: 81.1003
Option 2: 81.0113
Option 3: 81.1103
Option 4: 81.1013

Question

Question : If $\sqrt{5329}=73$, then the value of $\sqrt{5329}+\sqrt{53.29}+\sqrt{0.5329}+\sqrt{0.005329}+\sqrt{0.00005329}$ is:

Option 1: 81.1003

Option 2: 81.0113

Option 3: 81.1103

Option 4: 81.1013

Team Careers360 · Accepted Answer

Correct Answer: 81.1103

Solution : Given: $\sqrt{5329}=73$
$\sqrt{5329}+\sqrt{53.29}+\sqrt{0.5329}+\sqrt{0.005329}+\sqrt{0.00005329}$
Apply the square root rule,
$\sqrt{ab}=\sqrt{a} imes\sqrt{b}$
$\Rightarrow\sqrt{5329}+\sqrt{53.29} imes\frac{\sqrt{100}}{\sqrt{100}}+\sqrt{0.5329} imes\frac{\sqrt{10000}}{\sqrt{10000}}+\sqrt{0.005329} imes\frac{\sqrt{1000000}}{\sqrt{1000000}}+\sqrt{0.00005329} imes\frac{\sqrt{100000000}}{\sqrt{100000000}}$
$=\sqrt{5329}+\frac{\sqrt{5329}}{\sqrt{100}}+\frac{\sqrt{5329}}{\sqrt{10000}}+\frac{\sqrt{5329}}{\sqrt{1000000}}+\frac{\sqrt{5329}}{\sqrt{100000000}}$
Now replace $\sqrt{5329}$ to $73$.
$=73+\frac{73}{\sqrt{100}}+\frac{73}{\sqrt{10000}}+\frac{73}{\sqrt{1000000}}+\frac{73}{\sqrt{100000000}}$
$=73+\frac{73}{10}+\frac{73}{100}+\frac{73}{1000}+\frac{73}{10000}$
$=73+7.3+0.73+0.073+0.0073$
$=81.1103$
Hence, the correct answer is 81.1103.

Popular Searches

Question : If $\sqrt{5329}=73$, then the value of $\sqrt{5329}+\sqrt{53.29}+\sqrt{0.5329}+\sqrt{0.005329}+\sqrt{0.00005329}$ is:
Option 1: 81.1003
Option 2: 81.0113
Option 3: 81.1103
Option 4: 81.1013

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Question : If $\sqrt{5329}=73$, then the value of $\sqrt{5329}+\sqrt{53.29}+\sqrt{0.5329}+\sqrt{0.005329}+\sqrt{0.00005329}$ is:Option 1: 81.1003Option 2: 81.0113Option 3: 81.1103Option 4: 81.1013

Related Questions

Question : If $(2+\sqrt{3})a=(2-\sqrt{3})b=1$, then the value of $\frac{1}{a}+\frac{1}{b}$ is:Option 1: $1$Option 2: $2$Option 3: $2\sqrt{3}$Option 4: $4$

Question : If $n= 7+4\sqrt{3}$, the value of $(\sqrt{n}+\frac{1}{\sqrt{n}})$ is:Option 1: $2\sqrt{3}$Option 2: $4$Option 3: $-4$Option 4: $-2\sqrt{3}$

Question : If $r\sin\theta=1$, $r\cos\theta=\sqrt{3}$, then the value of $(\sqrt{3}\tan\theta+1)$ is:Option 1: $\sqrt{3}$Option 2: $\frac{1}{\sqrt{3}}$Option 3: $1$Option 4: $2$

Question : If $\sqrt{1+\frac{\sqrt{3}}{2}}-\sqrt{1-\frac{\sqrt{3}}{2}}=c$, then the value of $\mathrm{c}$ is:Option 1: 1Option 2: 4Option 3: 3Option 4: 2

Question : If $\sqrt{x}=\sqrt{3}-\sqrt{5}$, then the value of $x^2-16x+6$ is:Option 1: $0$Option 2: $-2$Option 3: $2$Option 4: $4$