Question : If $x:y=3:2$, then the value of $\frac{x+y}{x–y}$ is:
Option 1: $5:1$
Option 2: $1:3$
Option 3: $1:5$
Option 4: $3:1$
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Correct Answer: $5:1$
Solution :
Given: $x:y=3:2$
According to componendo and dividendo rule, if $\frac{a}{b}=\frac{c}{d}$, then $\frac{a+b}{a–b}=\frac{c+d}{c–d}$ have the same ratio.
Applying componendo and dividendo in the ratio $x:y=3:2$, we get,
⇒ $\frac{x+y}{x–y}=\frac{3+2}{3–2}$
⇒ $\frac{x+y}{x–y}=\frac{5}{1}$
Hence, the correct answer is $5:1$.
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